2x^2(x+1)=8(x+1)

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Solution for 2x^2(x+1)=8(x+1) equation: 



2x^2(x+1)=8(x+1)

We move all terms to the left:

2x^2(x+1)-(8(x+1))=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

2x^2(x+1)-8x-8=0

We move all terms containing x to the left, all other terms to the right

2x^2(x+1)-8x=8

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